-0.02d^2+192=0

Solution for -0.02d^2+192=0 equation:

-0.02d^2+192=0

a = -0.02; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-0.02)·192
Δ = 15.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{15.36}}{2*-0.02}=\frac{0-\sqrt{15.36}}{-0.04}
=-\frac{\sqrt{}}{-0.04}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{15.36}}{2*-0.02}=\frac{0+\sqrt{15.36}}{-0.04}
=\frac{\sqrt{}}{-0.04}
$